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Magnitudes Archaic: very conveninient if a) no calculations b) all stellar objects are blackbodies 3 - 10000 K (i.e. stars) c) use only photography in visual But still in use Take a star (alpha centuri): call it m=0 Take another star 100x fainter: call it m=5 Take another star 104xfainter: call it m=10 Algorithm for stars of same type as alpha centuri 1) Take number of times fainter I0/I 2) Take log10(I0/I) 3) Multiply by 2.5 exponential to the 2.51 power 2.51= What happens is spectrus not the same
Three standard magnitudes color excess MU, MB, MV scaled for standard star Could just quote flux densities at the 3 points magnitudes very misleading is bulk of flux is outside optical Sun 26.5 Faintest visible 6 Full Moon 13 Faintest Detectable 22 Sirius 1.5
Absolute Magnitude (M) m=M at 10 pc m at d m at 10 but m = -log2.51 Id = M = -log2.51 I10 M - m = -2.5 log Id + 2.5 log I10 = -2.5 log ( = -2.5 log ( = -5 log d + 5 log 10 M = m - 5 log d + 5
Astrophysical Plasma -Cosmic/Solar abundances What does it emit in various circumstances If we understand shysics then we can deduce circumstances of the matter All photons are generated by the acceleration of charged particles Will start with the simplest case:
Isolated charge
Relativistic Form:
(for colinear acceleration and velocity)
(for perpendicular acceleration and velocity)
We thus know the power here, but not the spectru. It gets complicates and E & M not appropriate here Qualitative approach: To become a photon electric field must be perturbed so that
vt
then we can get a photon if Therefore, wt < 1 for photon creation
Conservation of energy predicts a result like this. You cant put more energy into a photon than is lost from a particle. What can cause acceleration of a particle?
Collisions between particles and particles spiralling in B fields account for virtually all orgination of photons
Optically thin à photons escape as generated Optically Grey or Thick à photons interact with other matter before escaping We will now discuss emission mechanisms Synchrotron and Bremsstrahlung in optically thin case
Cyclotron Radiation B
v Non-relativistic particle Velocity = v Mass = m
With ensembles of particles: lines are not perfect d function
Widened by:
therefore, How does a particle behave in such a field?
but Therefore,
loses energy on a timescale
Radiates at
Synchrotron Radiation
Because of relativistic effects synchrotron does not radiate at fundamental frequency
In instantaneous rest from Larmor formula
Emits radiation at what particle thinks cyclotron frequency is, goes around at
Transform à Main Output at
described exactly as modified Bessel function Ensemble of Electrons Power law distribution of energy
convolve functions jn = emissivity per unit volume
Synchrotron Decay Time
P= 1.6 * 10-15 B2g2 ergs/s E= gmc2 =0.91*1027 * 9*1020 g ergs E=8.2*10-7 g ergs
therefore, B ~ 5 gauss g ~ 7
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